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Warning: getimagesize(image/): failed to open stream: Permission denied avec getimagesize



Posted by: ledisciple1
February 10, 2009 01:16PM
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<?php
$num_news=$_GET["num_news"];
?>

<?
$sql_info="select
news.date_news as date_news,
news.categorie_news as categorie_news,
news.texte_news as texte_news
from news join img on news.num_news=num_img
where news.num_news ='$num_news'
group by news.num_news";

$req_info = mysql_query($sql_info) or die('Erreur SQL !<br>'.$sql_info.'<br>'.mysql_error());

while($data = mysql_fetch_assoc($req_info))
{
echo '<table width="100%"><tr><td> '.$data['date_news'].'</td><td>'.$data['categorie_news'].'</td></tr><tr><td>'.$data['texte_news'].'</td></tr>';
}

$sql_img="select
nom_img
from news join img on news.num_news=img.num_img
where img.num_img ='$num_news'";

$req_img = mysql_query($sql_img) or die('Erreur SQL !<br>'.$sql_img.'<br>'.mysql_error());

list($width, $height, $type, $attr) = getimagesize('image/'.$data['nom_img']);

$ratio_width=($width*10/100);
$ratio_height=($height*10/100);
?>


<?php
while($data = mysql_fetch_assoc($req_img))
{
echo '<tr><td><a target="blank" href="image/'.$data['nom_img'].'"><img width="'.$ratio_width.'" height="'.$ratio_height.'" src="image/'.$data['nom_img'].'" /> </a></tr></td></table>';
}
?>
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Bonjour a tous.

J'ai un problème. Losque j'essaye d'utiliser la fonction getimagesize avec easy 1.8 le message suivant apparait : Warning: getimagesize(image/): failed to open stream: Permission denied.

Les chemins d'accès sont corrects et j'ai les permissions sur les images. Donc je ne vois plus qu'easy pour me barrer le chemin.

merci pour votre aide


sorry for my bad english

hello everybody

i've a problem. When I try to use function getimagesize with easy1.8, i have a message : Warning: getimagesize(image/): failed to open stream: Permission denied.

Url(s) haven't any problem and i've all permissions on the pictures.

thank you for your help